(2x-5)(x^2-7x+12)=0

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Solution for (2x-5)(x^2-7x+12)=0 equation: 


Simplifying
(2x + -5)(x2 + -7x + 12) = 0

Reorder the terms:
(-5 + 2x)(x2 + -7x + 12) = 0

Reorder the terms:
(-5 + 2x)(12 + -7x + x2) = 0

Multiply (-5 + 2x) * (12 + -7x + x2)
(-5(12 + -7x + x2) + 2x * (12 + -7x + x2)) = 0
((12 * -5 + -7x * -5 + x2 * -5) + 2x * (12 + -7x + x2)) = 0
((-60 + 35x + -5x2) + 2x * (12 + -7x + x2)) = 0
(-60 + 35x + -5x2 + (12 * 2x + -7x * 2x + x2 * 2x)) = 0
(-60 + 35x + -5x2 + (24x + -14x2 + 2x3)) = 0

Reorder the terms:
(-60 + 35x + 24x + -5x2 + -14x2 + 2x3) = 0

Combine like terms: 35x + 24x = 59x
(-60 + 59x + -5x2 + -14x2 + 2x3) = 0

Combine like terms: -5x2 + -14x2 = -19x2
(-60 + 59x + -19x2 + 2x3) = 0

Solving
-60 + 59x + -19x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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